If \( z = \frac{1}{2} - 2i \) is such that \( |z + 1| = \alpha z + \beta (1 + i) \), \( i = \sqrt{-1} \) and \( \alpha, \beta \in \mathbb{R} \), then \( \alpha + \beta \) is equal to:
\( -1 \)
\( 3 \)
\( 2 \)
\( -4 \)