The sum \( \displaystyle \sum_{n=1}^{\infty} \frac{2n^2 + 3n + 4}{(2n)!} \) is equal to:
\( \frac{11e}{2} + \frac{7}{2e} \)
\( \frac{13e}{4} + \frac{5}{4e} \)
\( \frac{13e}{4} + \frac{5}{4e} - 4 \)
\( \frac{11e}{2} + \frac{7}{2e} - 4 \)