If \( \frac{1}{2\cdot 3^{10}} + \frac{1}{2^{2}\cdot 3^{9}} + \ldots + \frac{1}{2^{10}\cdot 3} = \frac{K}{2^{10}\cdot 3^{10}} \) then the remainder when \( K \) is divded by \( 6 \) is:
\( 1 \)
\( 2 \)
\( 3 \)
\( 5 \)