The value of \( \dfrac{1\times 2^2 + 2\times 3^2 + \dots + 100\times (101)^2}{1^2\times 2 + 2^2\times 3 + \dots + 100^2\times 101} \) is:
\( \dfrac{305}{301} \)
\( \dfrac{32}{31} \)
\( \dfrac{31}{30} \)
\( \dfrac{306}{305} \)