The sum of all the real solutions of the equation \( \log_{(x+3)}(6x^2 + 28x + 30) = 5 - 2\log_{(6x+10)}(x^2 + 6x + 9) \) is equal to:
\( 4 \)
\( 2 \)
\( 1 \)
\( 0 \)