If \( 1 \), \( \log_{10}(4^{x}-2) \) and \( \log_{10}\!\left(4^{x}+\dfrac{18}{5}\right) \) are in arithmetic progression for a real number \( x \), then the value of determinant \(\displaystyle \begin{vmatrix} 2\left(x - \dfrac{1}{2}\right) & x - 1 & x^2 \\ 1 & 0 & x \\ x & 1 & 0 \end{vmatrix}\)is equal to: