The value of the limit \( \displaystyle\lim_{\theta \to 0} \dfrac{\tan\!\left(\pi \cos^{2}\theta\right)}{\sin\!\left(2\pi \sin^{2}\theta\right)} \) is equal to:
\( \dfrac{1}{4} \)
\( -\dfrac{1}{4} \)
\( -\dfrac{1}{2} \)
\( 0 \)