Let \( PQR \) be a triangle. The points \( A, B \) and \( C \) are on the sides \( QR, RP \) and \( PQ \) respectively such that \( \frac{QA}{AR}=\frac{RB}{BP}=\frac{PC}{CQ}=\frac{1}{2} \). Then \( \frac{\text{Area}(\triangle PQR)}{\text{Area}(\triangle ABC)} \) is equal to:
