The distance of the point \( (-1,9,-16) \) from the plane \( 2x+3y-z=5 \) measured parallel to the line \( \frac{x+4}{3}=\frac{2-y}{4}=\frac{z-3}{12} \) is:
\( 26 \)
\( 13\sqrt{2} \)
\( 20\sqrt{2} \)
\( 31 \)