Let the line passing through the points \( P(2,-1,2) \) and \( Q(5,3,4) \) meet the plane \( x-y+z=4 \) at the point \( R \). Then the distance of the point \( R \) from the plane \( x+2y+3z+2=0 \) measured parallel to the line \(\displaystyle \frac{x-7}{2}=\frac{y+3}{2}=\frac{z-2}{1} \) is equal to:
