If the \( 1011^{\text{th}} \) term from the end in the binomial expansion of \( \left( \dfrac{4x}{5} - \dfrac{5}{2x} \right)^{2022} \) is \( 1024 \) times \( 1011^{\text{th}} \) term from the beginning, then \( |x| \) is equal to:
\( 12 \)
\( 8 \)
\( 10 \)
\( 15 \)