Let \( A=\{(\alpha,\beta)\in R\times R :|\alpha-1|\le 4 \text{ and } |\beta-5|\le 6\} \) and \( B=\{(\alpha,\beta)\in R\times R:\ 16(\alpha-2)^{2}+9(\beta-6)^{2}\le 144\} \). Then
neither \( A\subset B \) nor \( B\subset A \)
\( A\subset B \)
\( B\subset A \)
\( A\cup B=\{(x,y):-4\le x\le 4,-1\le y\le 11\} \)