Assertion \( A \): If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is \( 5 \, \text{mm} \) and there are \( 50 \) total divisions on circular scale, then least count is \( 0.001 \, \text{cm} \).
Reason \( R \): Least Count \( = \dfrac{\text{Pitch}}{\text{Total divisions on circular scale}} \).
In the light of the above statements, choose the most appropriate answer from the options given below:
