A small liquid drop of radius \( R \) is divided into \( 27 \) identical liquid drops. If the surface tension is \( T \), then the work done in the process will be:
\( \dfrac{1}{8} \pi R^{2} T \)
\( 4 \pi R^{2} T \)
\( 8 \pi R^{2} T \)
\( 3 \pi R^{2} T \)