Two liquids \( A \) and \( B \) have \( \theta_A \) and \( \theta_B \) as contact angles in a capillary tube. If \( K = \cos \theta_A / \cos \theta_B \), then identify the correct statement:
\( K \) is zero, then liquid \( A \) has convex meniscus and liquid \( B \) has concave meniscus
\( K \) is negative, then liquid \( A \) and liquid \( B \) have convex meniscus
\( K \) is negative, then liquid \( A \) and liquid \( B \) have concave meniscus
\( K \) is negative, then liquid \( A \) has concave meniscus and liquid \( B \) has convex meniscus