The surface tension of a soap solution is \( 3.5\times 10^{-2} \, \text{N} / \text{m} \). The work required to increase the radius of a soap bubble from \( 1 \, \text{cm} \) to \( 2 \, \text{cm} \) is \( \alpha \times 10^{-6} \, \text{J} \). The value of \( \alpha \) is ______. \( \left( \pi=\dfrac{22}{7} \right) \)
