A slab of dielectric constant \( K \) has the same cross-sectional area as the plates of a parallel plate capacitor and thickness \( \dfrac{3}{4} d \), where \( d \) is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be:
(Given \( C_{0} = \) capacitance of capacitor with air as medium between plates.)
