A capacitor has air as dielectric medium and two conducting plates of area \( 12 \,\text{cm}^{2} \) and they are \( 0.6 \,\text{cm} \) apart. When a slab of dielectric having area \( 12 \,\text{cm}^{2} \) and \( 0.6 \,\text{cm} \) thickness is inserted between the plates. One of the conducting plates has to be moved by \( 0.2 \,\text{cm} \) to keep the capacitance same as in previous case. The dielectric constant of the slab is:
(Given \( \varepsilon_{0} = 8.834 \times 10^{-12} \,\text{F/m} \))
