If shortest wavelength of hydrogen atom in Lyman series is \\( x \\), then longest wavelength in Balmer series of \\( \\mathrm{He^+} \\) is:
\\( \\frac{9x}{5} \\)
\\( \\frac{36x}{5} \\)
\\( \\frac{x}{4} \\)
\\( \\frac{5x}{9} \\)