The correct set of four quantum numbers for the valence electron of rubidium atom \( (Z = 37) \) is:
\( 5, 1, 1, +\tfrac{1}{2} \)
\( 5, 0, 1, +\tfrac{1}{2} \)
\( 5, 1, 0, +\tfrac{1}{2} \)
\( 5, 0, 0, +\tfrac{1}{2} \)