A block of mass \( 5 \ \text{kg} \) is placed at rest on a table of rough surface. Now, if a force of \( 30 \ \text{N} \) is applied in the direction parallel to surface of the table, the block slides through a distance of \( 50 \ \text{m} \) in an interval of time \( 10 \ \text{s} \). Coefficient of kinetic friction is: (given \( g = 10 \ \text{m} / \text{s}^{2} \) )
