In Carius method, \( 0.75 \, \mathrm{g} \) of an organic compound gave \( 1.2 \, \mathrm{g} \) of barium sulphate, find percentage of sulphur (molar mass \( 32 \, \mathrm{g\,mol^{-1}} \)). Molar mass of barium sulphate is \( 233 \, \mathrm{g\,mol^{-1}} \).