Consider a uniform wire of mass \( M \) and length \( L \). It is bent into a semicircle. Its moment of inertia about a line perpendicular to the plane of the wire passing through the centre is:
\( \dfrac{M L^2}{\pi^2} \)
\( \dfrac{1}{2} \dfrac{M L^2}{\pi^2} \)
\( \dfrac{1}{4} \dfrac{M L^2}{\pi^2} \)
\( \dfrac{2}{5} \dfrac{M L^2}{\pi^2} \)