A particle of mass $m$ is projected with a velocity '$u$' making an angle of $30^\circ$ with the4 horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height $h$ is:
$\quad \frac{\sqrt{3}}{16} \frac{mu^3}{g}$
$\quad \frac{mu^3}{\sqrt{2}g}$
$\quad \frac{\sqrt{3}}{2} \frac{mu^2}{g}$
$\quad \text{zero}$
