What is the correct order of acidity of the protons marked A – D in the given compounds?
\( H_C > H_D > H_B < H_A \)
\( H_C > H_D > H_A > H_B \)
\( H_D > H_C > H_B > H_A \)
\( H_C > H_A > H_D > H_B \)
Identify the correct order of reactivity for the following pairs towards the respective mechanism.(A) (B) (C) Electrophilic substitution (D) Nucleophilic substitution Choose the correct answer from the options given below:
The standard reduction potentials at \( 298 \, \text{K} \) for the following half cells are given below:\( \mathrm{NO_3^-} + 4\mathrm{H^+} + 3e^- \rightarrow \mathrm{NO(g)} + 2\mathrm{H_2O} \quad E^\ominus= 0.97 \, \text{V} \)\( \mathrm{V^{2+}}(\mathrm{aq}) + 2e^- \rightarrow \mathrm{V} \quad E^\ominus = -1.19 \, \text{V} \)\( \mathrm{Fe^{3+}}(\mathrm{aq}) + 3e^- \rightarrow \mathrm{Fe} \quad E^\ominus = -0.04 \, \text{V} \)\( \mathrm{Ag^{+}}(\mathrm{aq}) + e^- \rightarrow \mathrm{Ag(s)} \quad E^\ominus = 0.80 \, \text{V} \)\( \mathrm{Au^{3+}}(\mathrm{aq}) + 3e^- \rightarrow \mathrm{Au(s)} \quad E^\ominus = 1.40 \, \text{V} \)The number of metal(s) which will be oxidized by \( \mathrm{NO_3^-} \) in aqueous solution is ________ .
In Dumas method for the estimation of \( \mathrm{N_2} \), the sample is heated with copper oxide and the gas evolved is passed over:
Compound from the following that will not produce precipitate on reaction with \( \mathrm{AgNO_3} \) is:
Choose the halogen which is most reactive towards \( \mathrm{S_{N}1} \) reaction in the given compounds (A, B, C and D)?
\( 2 \)-Methyl propyl bromide reacts with \( \mathrm{C_2H_5O^-} \) and gives ‘A’ whereas on reaction with \( \mathrm{C_2H_5OH} \) it gives ‘B’. The mechanism followed in these reactions and the products ‘A’ and ‘B’ respectively are:
Match List I with List II.Choose the correct answer from the options given below:
Find out the correct statement from the options given below for the above \( 2 \) reactions.
In the following given reaction ‘A’ is:
For the reaction \( \text{RCH}_2\text{Br} + \text{I}^- \xrightarrow{\text{Acetone}} \underset{\text{major}}{\text{RCH}_2\text{I}} + \text{Br}^-\) The correct statement is: