If the total energy transferred to a surface in time \( t \) is \( 6.48\times10^{5}\, \text{J} \), then the magnitude of the total momentum delivered to this surface for complete absorption will be:
\( 2.16\times10^{-3}\ \text{kg m}/\text{s} \)
\( 4.32\times10^{-3}\ \text{kg m}/\text{s} \)
\( 1.58\times10^{-3}\ \text{kg m}/\text{s} \)
\( 2.46\times10^{-3}\ \text{kg m}/\text{s} \)