A capacitor of capacitance \( 150.0 \, \mu \text{F} \) is connected to an alternating source of emf given by \( E = 36 \sin(120 \pi t) \, \text{V} \). The maximum value of current in the circuit is approximately equal to:
\( 2 \, \text{A} \)
\( \dfrac{1}{\sqrt{2}} \, \text{A} \)
\( \sqrt{2} \, \text{A} \)
\( 2\sqrt{2} \, \text{A} \)