The number of electrons flowing per second in the filament of a \( 110 \, \text{W} \) bulb operating at \( 220 \, \text{V} \) is:(Given \( e = 1.6 \times 10^{-19} \, \text{C} \))
\( 6.25 \times 10^{17} \)
\( 6.25 \times 10^{18} \)
\( 1.25 \times 10^{19} \)
\( 31.25 \times 10^{17} \)