The temperature of an ideal gas is increased from \( 200 \, \text{K} \) to \( 800 \, \text{K} \). If r.m.s. speed of gas at \( 200 \, \text{K} \) is \( v_0 \). Then, r.m.s. speed of the gas at \( 800 \, \text{K} \) will be:
\( 4v_0 \)
\( v_0 \)
\( \dfrac{v_0}{4} \)
\( 2v_0 \)