The length of a seconds pendulum at a height \( h = 2R \) from earth surface will be:(Given \( R \) = Radius of earth and acceleration due to gravity at the surface of earth, \( g = \pi^2 \, \text{ms}^{-2} \))
\( \dfrac{2}{9} \, \text{m} \)
\( \dfrac{4}{9} \, \text{m} \)
\( \dfrac{8}{9} \, \text{m} \)
\( \dfrac{1}{9} \, \text{m} \)