A block of mass \( 1 \, \text{kg} \) is pushed up a surface inclined to horizontal at an angle of \( 60^\circ \) by a force of \( 10 \, \text{N} \) parallel to the inclined surface as shown in figure. When the block is pushed up by \( 10 \, \text{m} \) along inclined surface, the work done against frictional force is:
[ \( g = 10 \, \text{m} /\, \text{s}^{-2} \) ]
