The correct order of basicity of oxides of vanadium is:
\( \mathrm{V_2O_3} > \mathrm{V_2O_4} > \mathrm{V_2O_5} \)
\( \mathrm{V_2O_4} > \mathrm{V_2O_3} > \mathrm{V_2O_5} \)
\( \mathrm{V_2O_3} > \mathrm{V_2O_5} > \mathrm{V_2O_4} \)
\( \mathrm{V_2O_5} > \mathrm{V_2O_4} > \mathrm{V_2O_3} \)