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The correct order in aqueous medium of basic strength in case of methyl substituted amines is:

Match List-I with List-II.

Choose the correct answer from the options given below:

The major products A and B from the following reactions are:

The compound which will have the lowest rate towards nucleophilic aromatic substitution on treatment with \( \mathrm{OH^-} \) is:

The major product for the following reaction is :

Given below are two statements.
Statement I: Pure Aniline and other arylamines are usually colourless.
Statement II: Arylamines get coloured on storage due to atmospheric reduction
In the light of above statements, choose the most appropriate answer from the options given below:

The product \( (P) \) formed from the following multistep reaction is:

Consider the following sequence of reactions:

The product ‘B’ is:

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): \( \alpha \)-halocarboxylic acid on reaction with dil \( \mathrm{NH_3} \) gives good yield of \( \alpha \)-amino carboxylic acid whereas the yield of amines is very low when prepared from alkyl halides.
Reason (R): Amino acids exist in zwitter ion form in aqueous medium.
In the light of the above statements, choose the correct answer from the options given below:

Compound P is neutral, Q gives effervescence with \( \mathrm{NaHCO_3} \) while R reacts with Hinsbergs reagent to give solid soluble in \( \mathrm{NaOH} \). Compound P is:

Match List I with List II.

Choose the correct answer from the options given below:

An organic compound \([A](\mathrm{C_4H_{11}N})\), shows optical activity and gives \( \mathrm{N_2} \) gas on treatment with \( \mathrm{HNO_2} \). The compound \([A]\) reacts with \( \mathrm{PhSO_2Cl} \) producing a compound which is soluble in \( \mathrm{KOH} \). The structure of \( A \) is:

Isomeric amines with molecular formula \( \mathrm{C_8H_{11}N} \) give the following tests
Isomer (P) ⇒ Can be prepared by Gabriel phthalimide synthesis.
Isomer (Q) ⇒ Reacts with Hinsberg’s reagent to give sold insoluble in \( \mathrm{NaOH} \).
Isomer (R) ⇒ Reacts with \( \mathrm{HONO} \) followed by \( \beta \)-naphthol in \( \mathrm{NaOH} \) to give red dye.
Isomers (P), (Q) and (R) respectively are:
P Q R

Compound A from the following reaction sequence is :

Number of isomeric aromatic amines with molecular formula \( \mathrm{C}_8\mathrm{H}_{11}\mathrm{N} \), which can be synthesized by Gabriel Phthalimide synthesis is \( \_ \_ \_ \_ \_ \_ \).

Given below are two statements:
Statement I: Sulphanilic acid gives esterification test for carboxyl group.
Statement II: Sulphanilic acid gives red colour in Lassaigne’s test for extra element detection.
In the light of the above statements, choose the most appropriate answer from the option given below:

The incorrect Statement regarding the reaction given below is:

The major product formed in the following reaction is:

In the above conversion of compound \( (X) \) to product \( (Y) \), the sequence of reagents to be used will be :

Reaction of propanamide with \( \mathrm{Br_2} / \mathrm{KOH(aq)} \) produces:

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JEE Main 2023 6th April Evening Shift

Number of isomeric aromatic amines with molecular formula \( \mathrm{C}_8\mathrm{H}_{11}\mathrm{N} \), which can be synthesized by Gabriel Phthalimide synthesis is \( \_ \_ \_ \_ \_ \_ \).