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Aldol condensation is a popular and classical method to prepare \( \alpha, \beta \)–unsaturated carbonyl compounds. This reaction can be both intermolecular and intramolecular. Predict which one of the following is not a product of intramolecular aldol condensation?

The product \( (A) \) formed in the following reaction sequence is:

Given below are two statements:
Statement (I) : Vanillin will react with \( \mathrm{NaOH} \) and also with Tollen’s reagent.

Statement (II) : Vanillin will undergo self aldol condensation very easily.

In the light of the above statements, choose the most appropriate answer from the options given below:

Both acetaldehyde and acetone (individually) undergo which of the following reactions?
\( \mathrm{A.} \) Iodoform Reaction \( \mathrm{B.} \) Cannizzaro Reaction \( \mathrm{C.} \) Aldol Condensation \( \mathrm{D.} \) Tollen’s Test \( \mathrm{E.} \) Clemmensen Reduction
Choose the correct answer from the options given below:

Consider the following molecules:

The correct order of rate of hydrolysis is:

Which of the following arrangements with respect to their reactivity in nucleophilic addition reaction is correct?

In the Claisen-Schmidt reaction to prepare, dibenzalacetone from \( 5.3 \, \mathrm{g} \) of benzaldehyde, a total of \( 3.51 \, \mathrm{g} \) of product was obtained. The percentage yield in this reaction was ________

The product \( (P) \) formed in the following reaction is:

Given below are two statements:
Statement I: Fructose does not contain an aldehydic group but still reduces Tollen's reagent.
Statement II: In the presence of base, fructose undergoes rearrangement to give glucose.
In the light of the above statements, choose the correct answer from the options given below

\( 0.1 \) mole of compound ‘S’ will weigh ______ g.
(Given molar mass in \( \text{g mol}^{-1} \) C : \( 12 \), H : \( 1 \), O : \( 16 \))

Which among the following compounds give yellow solid when reacted with \( \mathrm{NaOI}/\mathrm{NaOH} \)?

Choose the correct from the options given below:

A molecule (“P”) on treatment with acid undergoes rearrangement and gives (“Q”). (“Q”) on ozonolysis followed by reflux under alkaline condition gives (“R”). The structure of (“R”) is given below:

The structure of (“P”) is:

When undergoes intramolecular aldol condensation, the major product formed is:

“P” is an optically active compound with molecular formula \( \mathrm{C_6H_{12}O} \). When “P” treated with \( 2,4 \)-dinitrophenylhydrazine, it gives a positive test. However, in presence of Tollens reagent, “P” gives a negative test.
Predict the structure of “P”

Match List-I with List-II.

Choose the correct answer from the options given below :

The major product \( (P) \) in the following reaction is:

Residue \( (A) + \mathrm{HCl{(dil)}} \rightarrow \) Compound \( (B) \)
Structure of residue \( (A) \) and compound \( (B) \) formed respectively is:

Aman has been asked to synthesise the molecule \( (x) \). He thought of preparing the molecule using an aldol condensation reaction. He found a few cyclic alkenes in his laboratory. He thought of performing ozonolysis reaction on alkene to produce a dicarbonyl compound followed by aldol reaction to prepare “\( x \)”. Predict the suitable alkene that can lead to the formation of “\( x \)”.

Given below are two statements:
Statement (I): On nitration of m-xylene with \( \mathrm{HNO_3} , \mathrm{H_2SO_4} \), followed by oxidation, \( 4 \)-nitrobenzene-\( 1, 3 \)-dicarboxylic acid is obtained as the major product.
Statement (II): \( -\mathrm{CH_3} \) group is o/p-directing while \( -\mathrm{NO_2} \) group is m-directing group.
In the light of the above statements, choose the correct answer from the options given below:

The compounds which give positive Fehling’s test are:

Choose the correct answer from the options given below:

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JEE Main 2025 24th Jan Morning Shift

The product \( (A) \) formed in the following reaction sequence is: