What weight of glucose must be dissolved in \( 100 \, \text{g} \) of water to lower the vapour pressure by \( 0.20 \, \text{mm Hg} \)? (Assume dilute solution is being formed)
Given: Vapour pressure of pure water is \( 54.2 \, \text{mm Hg} \) at room temperature. Molar mass of glucose is \( 180 \, \text{g mol}^{-1} \).
When a non-volatile solute is added to the solvent, the vapour pressure of the solvent decreases by \( 10 \, \text{mm of Hg} \). The mole fraction of the solute in the solution is \( 0.2 \). What would be the mole fraction of the solvent if decreases in vapour pressure is \( 20 \, \text{mm of Hg} \)?
