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\( 17 \, \text{mg} \) of a hydrocarbon (M.F. \( \mathrm{C_{10}H_{16}} \)) takes up \( 8.40 \, \text{mL} \) of the \( \mathrm{H_2} \) gas measured at \( 0^\circ \text{C} \) and \( 760 \, \text{mm Hg} \). Ozonolysis of the same hydrocarbon yields

The number of double bond/s present in the hydrocarbon is _______.

Decreasing order of reactivity towards electrophilic substitution for the following compounds is:

Which of the following conformations will be the most stable?

The major product ‘\( P \)’ formed in the given reaction is:

The one giving maximum number of isomeric alkenes on dehydrohalogenation reaction is (excluding rearrangement)

Match List-I with List-II.

Choose the correct answer from the options given below

A hydrocarbon ‘X’ with formula \( \mathrm{C_6H_8} \) uses two moles of \( \mathrm{H_2} \) on catalytic hydrogenation of its one mole. On ozonolysis, ‘X’ yields two moles of methane dicarbaldehyde. The hydrocarbon ‘X’ is:

In the following reaction ‘X’ is:

\( 2-\text{Hexene} \xrightarrow[\text{(ii) }\text{H}_2\text{O}]{\text{(i) }\text{O}_3} \text{Product} \)
The two products formed in above reaction are:

Molar mass of the hydrocarbon \((X)\) which on ozonolysis consumes one mole of \( \mathrm{O_3} \) per mole of \((X)\) and gives one mole each of ethanal and propanone is ________ \( \text{g mol}^{-1} \).
(Molar mass of \( \mathrm{C} = 12 \, \text{g mol}^{-1} \), \( \mathrm{H} : 1 \, \text{g mol}^{-1} \))

But-\( 2 \)-yne is reacted separately with one mole of Hydrogen as shown below:

A. A is more soluble than B
B. The boiling point and melting point of A are higher and lower than B respectively.
C. A is more polar than B because dipole moment of A is zero.
D. \( Br_2 \) adds easily to B than A
Identify the incorrect statements from the options given below:

The major products ‘A’ and ‘B’, respectively, are:

The number of possible isomeric products formed when \( 3 \)-chloro-\( 1 \)-butene reacts with HCl through carbocation formation is ________.

Choose the correct set of reagents for the following conversion.
trans \( (\mathrm{Ph{-}CH{=}CH{-}CH_3}) \rightarrow \) cis \( (\mathrm{Ph{-}CH{=}CH{-}CH_3}) \)

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JEE Main 2023 12th April Morning Shift

\( 2-\text{Hexene} \xrightarrow[\text{(ii) }\text{H}_2\text{O}]{\text{(i) }\text{O}_3} \text{Product} \)
The two products formed in above reaction are: