The ratio of mass percentage \( (\text{w/w}) \) of \( \mathrm{C:H} \) in a hydrocarbon is \( 12:1 \). It has two carbon atoms. The weight \( (\text{in g}) \) of \( \mathrm{CO_{2}(g)} \) formed when \( 3.38\ \text{g} \) of this hydrocarbon is completely burnt in oxygen is:
(Given: Molar mass in \( \text{g mol}^{-1} \) \( \mathrm{C:12,H:1,O:16} \) )
