If \( y = y(x) \) is the solution curve of the differential equation \( (x^{2}-4)\,dy-(y^{2}-3y)\,dx=0, \, x>2, \, y(4)=\frac{3}{2} \) and the slope of the curve is never zero, then the value of \( y(10) \) equals:
\( \displaystyle\frac{3}{1+(8)^{1/4}} \)
\(\displaystyle \frac{3}{1-2\sqrt{2}} \)
\(\displaystyle \frac{3}{1+2\sqrt{2}} \)
\( \displaystyle\frac{3}{1-(8)^{1/4}} \)