The value of \( \cot\!\left( \displaystyle \sum_{n=1}^{50} \tan^{-1}\!\left(\frac{1}{1+n+n^{2}}\right)\right) \) is
\( \frac{26}{25} \)
\( \frac{25}{26} \)
\( \frac{50}{51} \)
\( \frac{52}{51} \)