\( \tan^{-1}\!\left(\frac{1+\sqrt{3}}{3+\sqrt{3}}\right) + \sec^{-1}\!\left(\sqrt{\frac{8+4\sqrt{3}}{6+3\sqrt{3}}}\right) \) is equal to:
\( \frac{\pi}{2} \)
\( \frac{\pi}{6} \)
\( \frac{\pi}{4} \)
\( \frac{\pi}{3} \)