The sum of all values of \( \theta \in [0, 2\pi] \) satisfying \( 2\sin^2\theta = \cos 2\theta \) and \( 2\cos^2\theta = 3\sin\theta \) is:
\(\displaystyle \frac{\pi}{2} \)
\( 4\pi \)
\( \pi \)
\(\displaystyle \frac{5\pi}{6} \)