Let in a right angled triangle, the smallest angle be \( \theta \). If a triangle formed by taking the reciprocal of its sides is also a right angled triangle, then \( \sin \theta \) is equal to:
\( \dfrac{\sqrt{5}-1}{4} \)
\( \dfrac{\sqrt{5}+1}{4} \)
\( \dfrac{\sqrt{5}-1}{2} \)
\( \dfrac{\sqrt{2}-1}{2} \)