Let \( f(x) = ax^3 + bx^2 + cx + 41 \) be such that \( f(1) = 40 \) , \( f'(1) = 2 \) and \( f''(1) = 4 \). Then \( a^2 + b^2 + c^2 \) is equal to:
\( 54 \)
\( 51 \)
\( 62 \)
\( 73 \)
