From a lot containing \( 10 \) defective and \( 90 \) non-defective bulbs, \( 8 \) bulbs are selected one by one with replacement. Then the probability of getting at least \( 7 \) defective bulbs is:
\( \frac{73}{10^{8}} \)
\( \frac{7}{10^{7}} \)
\( \frac{81}{10^{8}} \)
\( \frac{67}{10^{8}} \)