Let \( x \) be a random variable having binomial distribution \( B(7,p) \). If \( P(X = 3) = 5P(X = 4) \), then the sum of the mean and the variance of \( X \) is:
\( \frac{105}{16} \)
\( \frac{7}{16} \)
\( \frac{77}{36} \)
\( \frac{49}{16} \)