Let \( \overrightarrow{OA}=2\vec{a},\ \overrightarrow{OB}=6\vec{a}+5\vec{b} \) and \( \overrightarrow{OC}=3\vec{b} \), where \( O \) is the origin. If the area of the parallelogram with adjacent sides \( \overrightarrow{OA} \) and \( \overrightarrow{OC} \) is \( 15 \) sq. units, then the area (in sq. units) of the quadrilateral \( OABC \) is equal to:
