If the function \( f:(-\infty,-1)\to (a,b] \) defined by \( f(x) = e^{x^3-3x+1} \) is one – one and onto, then the distance of the point \( P(2b+4,a+2) \) from the line \( x+e^{-3}y=4 \) is:
\( 3\sqrt{1+e^6} \)
\( \sqrt{1+e^6} \)
\( 2\sqrt{1+e^6} \)
\( 4\sqrt{1+e^6} \)