Let the ellipse \( E_1 : \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1,\, a > b \) and \( E_2 : \frac{x^2}{A^2} + \frac{y^2}{B^2} = 1,\, A < B \) have same eccentricity \( \frac{1}{\sqrt{3}} \). Let the product of their lengths of latus rectums be \( \frac{32}{\sqrt{3}} \), and the distance between the foci of \( E_1 \) be \( 4 \). If \( E_1 \) and \( E_2 \) meet at \( A \), \( B \), \( C \) and \( D \), then the area of the quadrilateral \( ABCD \) equals: