If \( x^{2} + 9y^{2} - 4x + 3 = 0, \, x, y \in \mathbb{R} \), then \( x \) and \( y \) respectively lie in the intervals:
\( [1,\, 3] \) and \( \left[ -\dfrac{1}{3},\, \dfrac{1}{3} \right] \)
\( \left[ -\dfrac{1}{3},\, \dfrac{1}{3} \right] \) and \( \left[ -\dfrac{1}{3},\, \dfrac{1}{3} \right] \)
\( \left[ -\dfrac{1}{3},\, \dfrac{1}{3} \right] \) and \( [1,\, 3] \)
\( [1,\, 3] \) and \( [1,\, 3] \)