If the maximum distance of normal to the ellipse \( \frac{x^2}{4} + \frac{y^2}{b^2} = 1, \; b < 2 \), from the origin is \( 1 \), then the eccentricity of the ellipse is:
\( \frac{1}{2} \)
\( \frac{\sqrt{3}}{2} \)
\( \frac{\sqrt{3}}{4} \)
\( \frac{1}{\sqrt{2}} \)